Skip to content

Hebe - The Final! Mystery Cache

Hidden : 10/8/2013
Difficulty:
4.5 out of 5
Terrain:
3 out of 5

Size: Size:   micro (micro)

Join now to view geocache location details. It's free!

Watch

How Geocaching Works

Please note Use of geocaching.com services is subject to the terms and conditions in our disclaimer.

Geocache Description:

Asteroidbältet eller huvudbältet är det asteroidbälte som ligger i en ring runt solen. ”Bältet” befinner sig mellan planeterna Mars och Jupiter.

The asteroid belt is the region of the Solar System located roughly between the orbits of the planets Mars and Jupiter.


Hebe is the sixth discovered asteroid. Hebe is a large main-belt asteroid, containing around half a percent of the mass of the belt. Its apparently high bulk density, greater than that of the Earth's Moon or even Mars.


SWE
ENG

GLÖM INTE PENNAN!
DON'T FORGET TO BRING YOUR OWN PEN!

And now the mystery!

In number theory, a deficient number or defective number is a number n for which the sum of divisors σ(n)<2n, or, equivalently, the sum of proper divisors (or aliquot sum) s(n)<n. The value 2n − σ(n) (or n − s(n)) is called the number's deficiency.

The first deficient numbers are: 1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, …

In number theory, a perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself (also known as its aliquot sum). Equivalently, a perfect number is a number that is half the sum of all of its positive divisors (including itself) i.e. σ1(n) = 2n.


To solve the mystery Hebe - The final, obtain the codes in following caches:

You will find the cache at:

N 57 (11-1)*(11-2)*(10-3)*(9-4)*(8-5)+7*(1+11)*(4+11)+7*(4+2)+5*(5+5)+7

E 016 (1+2+3+4)*(9+10+11+11)*1+5*(5*7*8)-(1+2+3+4+5)*3-4*1+4

GeoCheck.org

Additional Hints (Decrypt)

N cresrpg ahzore. Zntargvp.

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)