Use the first instance of each (if there turns out to be more than one instance)
You know what to do..
Find the link between all the items and find a way to assign numbers to them. If I have included a red herring (or 3) then that letter has a value of 0
The cache is at:
N51 13.X W0 38.Y
where X = A+B+C+E+F+G+H+I+K+L
and Y = (D*H*B)+(L*C*E)+(D*K)+(A-B)
