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Nebojte se rizeni Mystery Cache

Hidden : 6/12/2012
Difficulty:
3.5 out of 5
Terrain:
1.5 out of 5

Size: Size:   micro (micro)

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Geocache Description:

Tato cache volne navazuje na nasi VOS a SPS Jicin. Zadani bude samozrejme opet trochu odborne. Cache na vychozich souradnicich nehledejte 
This cache freely connect at our VOS a SPS Jicin. The task will be again quite technical. Cache isn't at the start coordinates 


CR CZE
Tato kes vznikla jako nasledek meho proneseni pred zkouskou, ktere bylo takove, ze jestli dam zkousku, tak ze udelam dalsi kesku, kde priblizim sirsi verejnosti tento problem. Zavede do zakladu identifikace systemu a automatizace. Jelikoz se jedna o velice rozsahly a komplikovany obor, tak vam tu pouze nastinim jednoduché zacatky teto problematiky. Jedna se pouze o jeden priklad, který je pouze lehcim zlomkem cele problematiky a po jehoz vyreseni dostanete spravne souradnice cache.
Snazil jsem se o zajimave pojeti a poucne znazorneni pro lustitele, kde jsem si pripravil krom daneho prikladu i par obrazku pro pochopeni co vlastne kacer lusti
UK ENG
This cache rised as consequence of my delivery before exam which was that, if I will pass the exam, I will do the new cache as edification of this subject to wider public. It shows the begins of identification of system and automatization. Because it is very wide course, so I will show you only easy begins of this problematics. It will be only one task which is only the easier part of whole problematics and after the solving you get the right coordinates of cache.
I tried to make it easy and interesting conception and informative illustration for solver. Here are few pictures for better understanting and illustrating of this solving problem and what the solver solve
UK Ukol/Task
Mame zadanou vychozi prenosovou funkci nejakeho systemu (Fig. 1), ktera popisuje to, jak se bude system chovat, kdyz do neho pustime nejaky signal. Pro jednoduchost se uvazuje skokove napeti o velikosti 1 volt (Fig. 2). Pokud by byl system idealni, stejna hodnota i prubeh by byl ihned na vystupu, avsak v realu tomu takto neni. Realnemu systemu nejakou chvili trva, nez na pozadovanou hodnotu nabehne (Fig. 3).
We have given the initial transfer function of any system (Fig. 1), which describe the behaviour of the system, when we get at input any signal. For simplicity we reflect the step voltage with 1 volt (Fig. 2). If it will be the system ideal, the same value and course will be at output at the same time, but this is not reality. Real system need some time to get the required value (Fig. 3).

Transfer function
Fig. 1 Zadana prenosova funkce/Given transfer function

Pro jednoduchost si predstavme mysleny system jako napriklad sprintera. Ten celou dobu nic na startu nedela a pouze ceka, az dostane impuls ve forme startovniho vystrelu ke startu. V idealnim pripade by mel byt sprinter ihned ve chvili vystrelu jiz v cili, ale tak tomu neni. Chvili mu trva, nez do cile dobehne. A uplne stejne je to i u tech realnych systemu. Take jim chvili trva, nez se prizpusobi pozadavkum, ktere jim privadime na vstup.
For simplicity suppose the thinking system as e.g. sprinter. This doing nothing for all the time at start line and only waiting for the impuls which get as starting shot. In ideal case will be the sprinter in the finish at the sime time of shot, but this no happend. He needs some time to get to finish. And the same is at the real systems. They have some delay to adapt at request at input.

Simulating scheme
Fig. 2 Simulacni schema dane funkce/Simulate scheme of given transfer function


Simulated courses
Fig. 3 Nasimulovany prubeh dane prenosove funkce/Simulated courses of given transfer function

O rychlosti, s jakou sprinter dobehne do cile rozhoduji jiste parametry. U sprintera je to prave jeho fyzicka kondice, jake ma tretry, delka nohou a kroku, ... Kdezto u elektrickeho systemu jsou to nejake konstanty, ktere urcuji jeho kvalitu a vlastnosti. A prave na tyto vlastnosti se ptame v teto mysterce. Dokazete vyresit zakladni charakteristiku nejakoho systemu, pro ktery mate pouze zakladni prenosovou funkci? Pro ulehceni jsme vam jiz zakladni vztah napsali (Fig. 4) a je jen na vas, zdali spravne dosadite a upravite danou prenosovou funkci tak, aby vse souhlasilo.
About speed, which the spinter get to finish, decide any parameters. At sprinter they are physical condition, how shoes he wears, size of his leg and distance of his step, ... But at electric system are they any constants, which describe its quality and properties. And at this constants we are asking in this mystery cache. Will you be able to solve the basic characteristics of this system for what you get only the basic transfer function? For simplicity we give you the basic equation (Fig. 4) and depend ony at you, if you will be correct in establishing and correct the given function to correct form for good results to get the right coordinates.

Transfer function 2
Fig. 4 Pozadovana prenosova funkce/Required transfer function

kde: K...zesileni systemu, T1 a T2...casove konstanty systemu, s...Laplaceovy operátory
where: K...gain of the system, T1 and T2...time constants of system, s...Laplace operators

Finalni souřadnice/Final coordinates:


! T1>T2 !

N 50° (T2-(K-14))T1, T1(T1-(K-14))(T1+T2-(K-14)
E 015° (T2-(K-14))(T1-T2-2*(K-14)), (2*T1-(K-14))(T1+T2-(K-14))(T1+T2)

Kontrolni soucet celkovych N souradnic/Control summ of total N coordinates: 28
Kontrolni soucet celkovych E souradnic/Control summ of total E coordinates: 32

Click to verify coordinates


V pripade jakychkoli problemu s resenim nas nevahejte kontaktovat pres nase ucty. Radi vam pomuzeme s resenim v co nejkratsi dobe to bude mozne.
If you will have any problems with solving, please don't affraid and contact us via our accounts. We will pleased to help you with silwing in what the shortest time it will be possible.


V kesi neni tuzka!/The pen is not in cache!
Editováno 16.6.2012 - děkuji za připomínku od Bolka*59*Eirea za chybičku s evinkou. Vše by již nyní mělo souhlasit. :)
Editováno 25.6.2012 - Opravena chyba ve vzorci a kontrolní součet - omlouvám se za chybu a případné problémy s luštěním. Nyní by již snad vše mělo souhlasit

Additional Hints (Decrypt)

Erfrav/Fbyivat: Zngrzngvxn MF/Onfvp fpubby zngu Svanyxn/Svany: Ivgrwgr!/Or jryypbzr!

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)