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1756 Homolka (Prussian artillery) Mystery Cache

This cache has been archived.

solimv: Dnes jsem se prošel zabahněným polem a odstranil poslední zbytky přítomnosti schránky.

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Hidden : 9/20/2008
Difficulty:
3 out of 5
Terrain:
1.5 out of 5

Size: Size:   regular (regular)

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Geocache Description:


1756 Homolka (Prussian artillery)


[CZ]

Od 10.7.2010 je cache na novych souradnicich. Pokud mate vypocitane stare, pak N + 0.039, E - 0.090

Cache je umistena priblizne na pozicich delostrelecke baterie, odkud ridil 1.rijna 1756 v bitve u Lovosic kral Fridrich II. pruske jednotky.

Bitva u Lovosic byla prvni bitvou Sedmilete valky. Probehla 1. rijna 1756 zapadne od Lovosic. Prusky kral Fridrich II. Veliky zautocil s priblizne tricetitisicovym vojskem ze svahu nad Lovosicemi na obranne postaveni rakouske armady s 33 000 muzi, ktere vedl rakousky general Maximilian Ulysses von Browne. Boje trvaly jeden den. Ztraty byly vyrovnane, na obou stranach padlo cca 3000 vojaku. Bitva nemela jednoznacneho viteze.

Podrobnosti na Wikipedii nebo Kronoskaf (anglicky) 

K nalezeni cache musite vyresit nize uvedenou delostreleckou ulohu

Pozice pruskeho dela je na vrcholku vyvyseniny nad obci Sulejovice. Delo ma hlaven ve vodorovne pozici (neni nakloneno smerem vzhuru ani dolu) a strili koule o hmotnosti 12 videnskych liber na rakouskou pechotu dole v obci. Prima vzdalenost vzdusnou carou od usti hlavne do cile je 1013 videnskych sahu. Vrchol kopce na kterem stoji delo je o 45 videnskych sahu vyse nez je vesnice.

Vasim ukolem je zjistit, jake mnozstvi strelneho prachu bude potreba na jeden vystrel, jestlize vite, ze se rychlost projektilu ve vztahu k mnozstvi pouziteho strelneho prachu zvysuje linearne (5 lotu cerneho strelneho prachu udeli projektilu rychlost 28 m/s, 10 lotu strelneho prachu mu udeli rychlost 88 m/s atd.). Zanedbavame treni, odpor vzduchu i vysku budov v obci (znalci laskave prominou zjednoduseni). Vysledne cislo v lotech zaokrouhlite na cela cisla a ziskate tak dvouciferne cislo XY. Nyni muzete vypocitat cilove souradnice:

N 50° 30.[720-8*XY+39] E 014° 01.[341-XY-90]


[EN]

Final coordinates were changed 10.7.2010. You can get new coordinates from the old => N + 0.039 E - 0.090

The cache is placed near Prussian artillery position, the point from which led Prussian king Frederick the Great his army to the battle on October 1, 1756.

The Battle of Lobositz was a battle fought on October 1, 1756 during the Seven Years' War. A Prussian army of about 30,000 men fought an Austrian army of 33,000 men. The Prussian army was led by Frederick the Great, the Austrian army by Field marshall von Browne. The Prussians and the Austrians lost approximately 3,000 men each. The battle didn't have clear winner.

For more details see Wikipedia, Kronoskaf or Knowledgerush  

You have to solve the artillery test bellow to gain right cache coordinates.

There is a Prussian cannon on the summit of a small hill near village Sulejovice. A gun barrel is in vertical position (it doesn’t aim downhill or uphill). The cannon shoots cannonball which weighs 12 Vienna Pfunds (old Austrian unit of weight) to the Austrian infantry located in the village. There is 1013 Vienna Klafters (old Austrian unit of length) direct distance between gun barrel’s mouth and the target (straight line). The cannon is on the summit of hill – there is 45 Vienna Klafters vertical difference between cannon and the target.

You have to count up the quantity of gunpowder which you need to load the cannon to hit the target. There is a linear function between quantity of gunpowder and the speed of cannonball. You know that the cannon needs 5 ounces of gunpowder to reach the cannonball speed of 28 m/s, 10 ounces of gunpowder to reach the speed of 88 m/s etc. Air resistance, friction and height of buildings are insignificant. Round the weigh of gunpowder (in ounces) and you will get two digit natural number = XY. Now you can calculate the final coordinates.

N 50° 30.[720-8*XY+39] E 014° 01.[341-XY-90]

Click to verify coordinates

Additional Hints (Decrypt)

[CZ]ivfv (1,5z) [EN]vg unatf (1,5z)

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)